How big is the heat generated by Led
LEDs generate heat because they emit light. How much heat does the LED produce? How do we choose a radiator?How to choose the IC driver?
LED heat prevention and reduction:
Like traditional light sources, semiconductor light-emitting diodes (LEDs) also generate heat during operation, depending on the overall luminous efficiency. Under the action of external electric energy, the radiation of electrons and holes recombines to produce electroluminescence, and the light radiated near the P-N junction needs to pass through the semiconductor medium and the package medium of the chip itself to reach the outside (air).
Comprehensive current injection efficiency, radiant luminescence quantum efficiency, external light extraction efficiency of the chip, etc.,
Finally only about 30-40% of the input electrical energy is converted into light energy, of which 60-70% of the energy is mainly caused by non-radiative recombination lattice vibration. Form converts heat.
The increase in the temperature of the chip enhances the non-radiative recombination and further weakens the luminous efficiency. Because people subjectively believe that high-power LEDs have no heat.
A lot of heat, so that problems occur during use. In addition, many people who use high-power LEDs for the first time do not know how to solve the heat problem effectively, which makes product reliability a major problem. So, is there any heat generated by the LED? How much heat can you produce? How big is the heat generated by the LED?
At the forward voltage, the electrons receive energy from the power source. Under the driving of the electric field, the electric field of the PN junction is overcome, and the N region transitions to the P region.
These electrons recombine with the holes in the P region. Since the free electrons drifting to the P region have energy higher than that of the P region valence electrons, the electrons return to the low energy state at the time of recombination, and the multi-turn energy is released in the form of photons. The wavelength at which the photons are emitted is related to the energy difference Eg.
Therefore, the illuminating region is mainly near the PN junction, and the luminescence is the result of the release of energy by the recombination of electrons and holes. With a semiconductor diode, electrons encounter resistance throughout the journey from the semiconductor region to the semiconductor region. Simply from the principle, the physical structure of the semiconductor diode is simply from the principle, the physical structure of the semiconductor diode is equal to the electrons emitted from the negative electrode and the number of electrons returning to the positive electrode. In a common diode, the recombination of electron-hole pairs occurs due to the difference in energy level Eg, and the released photon spectrum is not in the visible range.
When electrons are inside the diode, power is consumed due to the presence of resistance.
—The power consumed is in accordance with the basic laws of electronics:
*P =I2 R =I2（RN ++RP ）+IVTH
Where: RN is the N-body resistance and RP is the P-region resistance.
—The heat generated by the power consumed is:
*Q = Pt
Where: t is the time when the diode is energized.
In essence, the LED is still a semiconductor diode. Therefore, when the LED is working in the forward direction, its working process conforms to the above description. The electric power it consumes is:
*P LED = U LED &TImes; I LED
Where: U LED is the forward voltage across the LED source
The I LED is the current that flows through the LED.
These consumed electrical power is converted into heat release:
*Q=P LED &TImes/t
Where: t is the power-on time
In fact, the energy released by the electrons in the P region and the holes are not directly supplied by the external power source, but because the electrons are in the N region, when there is no external electric field, its energy level is better than that of the P region.
The valence electron energy level is higher than Eg. When it reaches the P zone, it recombines with the hole to become the valence electron of the P zone, and it releases this? N more energy. The size of the Eg is determined by the material itself and is independent of the external electric field. The effect of the external power supply on the electrons is only to push it to do directional movement and overcome the role of the PN junction.
The heat production of LEDs has nothing to do with light efficiency. There is not a few percent of the electrical power generating light, and a few percent of the electrical power creates a thermal relationship. Through the understanding of high-power LED heat generation, thermal resistance, junction temperature concept and theoretical formula derivation and thermal resistance measurement, we can study the actual package design, evaluation and product application of high-power LED.
It should be noted that thermal management is a key issue at the current stage of low luminous efficiency of LED products. It is the bottom line to fundamentally improve the luminous efficiency to reduce the generation of thermal energy, which requires chip manufacturing, LED packaging and application product development. Advances in technology at all stages.
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